

![]()
Prepared by:-
Alan Twaddle
30th October 2008
Brief
You are working in a Building Services Consultants office and are
tasked with the job of designing building services systems for domestic and
commercial buildings.
You will use all available guidelines and legislation to
complete working designs of an air conditioning system for a commercial
building.
Consult relevant documents such as; CIBSE guides, Building
Regulations, HVCA documents, European and British standards.
Your brief includes some preliminary data searches and
compilation of relevant information.
The initial design will examine natural ventilation and the
possibility of using it to save energy in the project building.
Design calculations will be carried out at the initial stages of
the design to size plant and equipment and provide energy efficient services
systems that meet all performance criteria for energy consumption.
The evaluation of heat gains is an important step in
ascertaining whether or not air conditioning is required in a building. Your
design should include details of air conditioning systems from information
gathered from appropriate sources.
QUESTION NO. 1
QUESTION NO. 1
Ventilation and air conditioning
needs
1.
Produce a table of inside environmental design requirements for
the Leisure Centre building.
Typical
Internal Design Criteria -
|
Room |
Internal
Temperatures Deg
C |
Relative
Humidity |
Ventilation Lts/person |
Lighting
Levels Lux |
Noise
Rating |
|
Offices |
Winter Summer 19 min Uncontrolled |
Uncontrolled |
12 - 24 |
300 |
NR35 |
|
Fitness Suite |
16 min. 23 |
Uncontrolled |
12 - 24 |
300 |
NR40 |
|
Foyer |
18 min. Uncontrolled |
Uncontrolled |
N/A |
200 |
NR40 |
|
Restaurant |
19 min. Uncontrolled |
Uncontrolled |
12 |
150/300 |
NR40 |
|
Reception |
19 min. Uncontrolled |
Uncontrolled |
12 |
150/300 |
NR40 |
|
Toilets |
18 min. Uncontrolled |
Uncontrolled |
10ac/h Extract Only |
200 |
NR45 |
|
Changing Areas (Dry) |
20 min. Uncontrolled |
Uncontrolled |
10ac/h Extract 8ac/h Supply |
200 |
NR45 |
To follow
: - Typical Internal Design Criteria
- Leisure Centre Building Other Areas if Applicable
|
Swimming Pool |
29 min.
29 min. +- 1 +- 1 |
50-70 % |
10l/s /m2 |
600 |
NR45 |
|
Changing Areas (Wet) |
25 min. Uncontrolled |
Uncontrolled |
10ac/h Extract 8ac/h Supply |
200 |
NR45 |
QUESTION NO. 2
QUESTION NO. 2
2.
Determine, using a psychrometric chart,
the heater battery and cooling coil outputs and the supply air temperature for
the Activity Room in the Leisure Centre.
ROOM
CONDITION DESIGN
16
deg. C , 50 % sat ( CIBSE Guide A Table 1.5 )
Outside
Design Conditions
27
deg. C, 80% sat.
Ventilation
rate = 10 AC/H ( CIBSE Guide A, table 1.5 )
Fresh
air vent rate = 24 l/s/person x 30 persons = 720 l/s = 0.72 m3/s. volume flow rate
Mass
flow rate = M = VxD = 0.72 x 1.2 = 0.864
Kg/s.
Fresh
Air rate in AC/H = 0.72 x 3600 = 2592
m3/h
2592
/ volume (21x18x4.5) = 2592 / 1701 = 1.52
AC/H
%
fresh Air = 1.5 / 10 = 0.15 x 100 = 15% fresh Air.
Mix
ratio = 15% fresh Air 85%
recirc
Cooling Coil Output
The
cooling coil output is as follows:
H cooling coil = ma
(hM - hADP)
where:
H cooling coil = Cooling coil output (kW)
ma = mass
flow rate of air (kg/s)
hM = specific
enthalpy at condition M (kJ/kg) determined from psychrometric chart.
hADP = specific
enthalpy at condition ADP (kJ/kg) determined from psychrometric chart
The specific enthalpies at points M and ADP
are shown on the psychrometric Chart above.
H cooling coil = 0.864
( 37 - 19 )
H cooling coil = 15.55 kW
Reheater
The
heater battery or reheater output is as follows:
H heater battery = ma ( hS - hW)
where:
H heater battery = Heater battery output (kW)
ma = mass
flow rate of air (kg/s)
hS = specific
enthalpy at condition S (kJ/kg) determined from psychrometric chart.
hW = specific
enthalpy at condition W (kJ/kg) determined from psychrometric chart.
The specific enthalpies at points W and S
are shown on the psychrometric Chart above.
H heater battery
= 0.864
( 29 - 19 )
H heater battery
= 8.64 kW
Note calculation based on Summer time only i.e.
cooling coil for summer conditions and reheater for summer conditions to remove
moisture.
QUESTION NO. 3
3.
Discuss
the possibility of using mechanical ventilation instead of air conditioning in
the Leisure Centre building.
Air Conditioning and Ventilation
Ventilating buildings is an important part of forming
comfortable spaces for work and living. Enhanced building regulations have
improved U-values but convective heat losses have increased. Energy consumption has risen significantly due to
often unnecessary increase in the use of air conditioning in many buildings.
It has also been realised how much energy can be lost as a result of
uncontrolled air passing through leaky buildings. A vital part of improving
building energy performance is getting the issues right at the design stage.
Ventilation and air conditioning systems come in many types but whether
natural, mechanical or a combination of the two, they need to have a good
degree of local control and meet health, comfort and cooling needs. A crucial
factor in energy efficiency is defining the optimum ventilation rate as
conditions such as excessive fresh air will cause excessive energy consumption
while an inadequate amount of fresh air will see a rapid decline in internal
air quality. 5 litres/sec per person is the minimum required rate though the recommended
rate is 10 litres/sec per person. An advised strategy is to avoid smoking in
buildings or provide separately ventilated rooms for smokers as cigarette
smoking can double or quadruple this requirement.
Air Conditioning - Build tight, ventilate right!
The greatest energy loss from buildings is often
from ventilation though the importance of this has become more apparent as
conduction losses have been reduced with improved levels of insulation.
Therefore it is important that a tight envelope is developed from the design
stage to minimise uncontrolled air infiltration. A common rule for both
mechanical and naturally ventilated buildings is “Build tight, ventilate
right”. To minimise air leakage and infiltration, attention to detailing and
sealing is paramount. The common points of infiltration include gaps around the
perimeter of doors and windows, the areas where door and window frames meet a
wall and the junctions of walls, ceilings and floors. Often the blame lies with
poor workmanship, especially in service ducts. Very large energy losses in
existing buildings and some recently built buildings are often through
uncontrolled ventilation and are worse than the minimum standards which are
often easily achievable. Controlled ventilation is essential in tight buildings
as they can have problems unique to them such as a total lack of ventilation
can lead to mould growth and other similar problems.
A move to a mechanical ventilation or air
conditioning system
If possible, it is advisable to use natural
ventilation rather than instantly opting for Air Con solutions
which rely on mechanical systems. Buildings that are naturally ventilated tend
to use less energy than those with mechanical based ventilation and air
conditioning. Driving force for air movement is generated by a stack effect
which is achieved by using air passages at different heights and wind effects.
This is often achieved by ventilating from at least two facades. Buildings that
rely on natural ventilation generally provide advantages such as lower energy
consumption leading to lower running costs, the transport energy associated
with fans is reduced, the risk of possible plant noise
is reduced and capital and maintenance costs are
reduced. High levels of noise or pollutants and other external environmental
conditions which may limit or preclude natural ventilation usage need
to be identified at an early stage and minimised
where it is possible. If windows have been kept shut to keep out noise, fumes,
dirt or smoke, it may mean a move to a mechanical ventilation or air
conditioning systems which will result in higher energy consumption. A most
important factor in
successful natural ventilation strategies is the minimisation
of internal heat gains. When trying to retain a natural ventilation solution,
efficient lighting, office equipment and solar shading are all beneficial, with
40W/m2 generally regarded as excessive and subject to assessment previous to
the selection of a ventilation strategy. The need for mechanical cooling can
also be avoided by using night air to cool the building fabric. Incidentally,
the building fabric can absorb the incidental gains during the occupied hours
and act as a heat sink which can be used as a thermal store.
Many buildings have air conditioning installed simply as it is
seen as the best solution or for the reason of higher rental value that comes
with that. Mechanical ventilation and air conditioning are energy intensive
processes and factors such as noise, pollution, excessive heat gains can
prevent a passive solution meaning that designers need to consider the next
best energy efficient means of providing ventilation. There are a range of
mixed mode solutions that can provide intermediate options and involve a
variety of ventilation and cooling systems. An example is to rely on
ventilation and cooling by opening windows and turning off the air conditioning
for parts of the season. Another example is zoning which works by keeping the
bulk of the building naturally ventilated while massing all significant heat
producing equipment into a space with the appropriate air conditioning.
Full Air Conditioning
When a full air conditioning system is added to a
design it can add up to 50 percent to the total running costs for the building
and therefore, should be very carefully considered. While full air conditioning
involves humidity control, the
The fact that mechanical ventilation requires
higher air change rates than those in naturally ventilated buildings leads to
increased HV AC running and capital costs. One of the largest energy users in
offices with air conditioning is air handling and this is often a much greater
amount of energy use than chillers. The typical use if air handling in offices
is 42-44kWh/m2/yr though best practice installations can roughly half that.
Often, systems are over installed and greater than 12W/m2 is excessive while
best practice is around 8W/m2. Therefore, sizing the fan is important as it
needs to be as close to the real demand as possible to avoid unnecessary costs.
The fan power which is a measure of the fans efficiency should be kept as low
as possible. Good practice for offices is below 2W/litre/second and with very
energy efficient systems; 1W/litre/second can be achieved. Anything above
4W/litre/second can be regarded as having a poor standard of efficiency and
many existing systems are oversized with poor fan power. This can be prevented
by matching equipment closely to demand and specifying high efficiency fans and
motors.
Minimise energy consumed in air conditioning
Measures to minimise energy consumed in air conditioning are included in Building
Regulations Part L2. This includes the necessary requirements for refurbished and
new buildings as well as existing
buildings with an air conditioning or ventilation
system is due to be altered or replaced. Showing that the Carbon Performance
Rating (CPR) falls within certain limits is a way if achieving compliance in
office environments.
Another way of achieving compliancy in offices is
meeting ‘Whole Office’ CPR targets. Meeting specific fan power targets in other
buildings requires 2W/litre/sec in new buildings, 3W/litre/sec in
refurbishments while schools and hospitals comply by following DFEE and NHS
guidelines.
QUESTION NO. 4
4.
Discuss
the possibility of using natural ventilation as a means of cooling the Fitness suites
and Activity area of the Leisure Centre.
Design a suitable natural ventilation system for these
areas.
Design
for Natural Ventilation
The design of controlled natural ventilation systems
requires identification of the prevailing wind direction, the strategic
orientations and positions of openings on the building envelope. These openings
include windows, doors, roof ventilators, skylights, vent shafts, and so forth.
Ventilation
rates
When designing a ventilation system, the
ventilation rates are required to determine the sizes of fans, openings, and
air ducts. The methods that can be used to determine the ventilation rates
include:
(a) Maximum allowable concentration of
contaminants
A decay equation can be used to describe the
steady-state conditions of contaminant concentrations and ventilation rate,
like this:
|
Ci = Co
+ F / Q |
(3) |
|
where |
Ci |
= maximum allowable concentration of
contaminants |
|
|
|
Co |
= concentration of contaminants in outdoor
air |
|
|
|
F |
= rate of generation of contaminants
inside the occupied space (l/s) |
|
|
|
Q |
= ventilation rate (l/s) |
|
(b) Heat generation
The ventilation rate required to remove heat from an
occupied space is given by:
|
|
(4) |
|
where |
H |
= heat generation inside the space (W) |
|
|
|
Q |
= ventilation rate (l/s) |
|
|
|
cp |
= specific heat capacity of air (J/kg.K) |
|
|
|
|
= density of air (kg/m3) |
|
|
|
Ti |
= indoor air temperature (K) |
|
|
|
To |
= outdoor air temperature (K) |
|
Air
change rates
Most related professional institutes and
authorities have set up recommended ventilation rates, expressed in air change per
hour, for various situations. The ventilation rate is related to the air change
rate by the following equation:
|
|
(5) |
|
where |
Q |
= ventilation rate (l/s) |
|
|
|
V |
= concentration of contaminants in outdoor
air |
|
|
|
ACH |
= air change per hour |
|
Flow
caused by wind
Major factors affecting ventilation wind forces
include:
average wind speed;
prevailing wind direction;
seasonal and daily variation in wind speed and
direction;
local obstructing objects, such as nearby buildings
and trees;
position and characteristics of openings through
which air flows; and
distribution of surface pressure coefficients for
the wind.
Natural ventilation systems are often designed for
wind speeds of half the average seasonal velocity because from climatic
analysis there are very few places where wind speed falls below half the
average velocity for many hours in a year.
The following equation shows the air flow rate
through ventilation inlet opening forced by wind:
|
|
(6) |
|
where |
Q |
= air flow rate (m3/s) |
|
|
|
A |
= free area of inlet openings (m2) |
|
|
|
v |
= wind velocity (m/s) |
|
|
|
Cv |
= effectiveness of the openings (assumed
to be 0.5 to 0.6 for perpendicular winds and 0.25 to 0.36 for diagonal winds) |
|
Flow
caused by thermal forces
If the building's internal resistance is not
significant, the flow caused by stack effect may be estimated by:
|
|
(7) |
|
where |
Q |
= air flow rate (m3/s) |
|
|
|
K |
= discharge coefficient for the opening
(usually assumed to be 0.65) |
|
|
|
A |
= free area of inlet openings (m2) |
|
|
|
|
= height from lower opening (mid-point) to
neutral pressure level (m) |
|
|
|
Ti |
= indoor air temperature (K) |
|
|
|
To |
= outdoor air temperature (K) |
|
Guidelines
for natural ventilation
The following guidelines are important for planning
and designing natural ventilation systems in buildings:
a natural ventilation system should be effective regardless
of wind direction and there must be adequate ventilation even when the wind
does not blow from the prevailing direction;
inlet and outlet openings should not be obstructed
by nearby objects;
windows should be located in opposing pressure
zones since this usually will increase ventilation rate;
a certain vertical distance should be kept between
openings for temperature to produce stack effect;
openings at the same level and near the ceiling
should be avoided since much of the air flow may bypass the occupied zone;
architectural elements like wingwalls, parapets and
overhangs may be used to promote air flow into the building;
topography, landscaping, and surrounding buildings
should be used to redirect airflow and give maximum exposure to breezes;
in hot, humid climates, air velocities should be
maximised in the occupied zones for bodily cooling;
to admit wind air flow, the long façade of the
building and the door and window openings should be oriented with respect to
the prevailing wind direction;
if possible, window openings should be accessible
to and operable by occupants;
vertical shafts and open staircases may be used to
increase and generate stack effect;
openings in the vicinity of the neutral pressure
level may be reduced since they are less effective for thermally induced
ventilation; if inlet and outlet openings are of nearly equal areas, a balanced
and greater ventilation can be obtained.
Barriers
to the application of natural ventilation
A successful application of natural ventilation
strategies is only possible when there are no problems in many areas at various
levels from the design stage to actual operating demands placed on the building
users (Allard, 1998). These potential barriers include:
Barriers during building operations
Safety concerns
Noise from outdoor
Dust and air pollution
Solar shading covering the openings
Draught prevention
Knowledge of the users about how to take the best
advantage of natural ventilation
Barriers during building design
Building and fire regulations
Need for acoustic protection
Difficult to predict pattern of use
Devices for shading, privacy & daylighting may
hamper the free flow of air
Problems with automatic controls in openings
lack of suitable, reliable design tools
Other barriers
Impact on architectural & envelope design
Fluctuation of the indoor conditions
Design a naturally ventilated building requires
more work but could reduce mechanical system (design fee on a fixed percentage
of system's cost)
Increase risk for designers
Lack of suitable standards
Infiltration
and Air Leakage
Infiltration is the uncontrolled flow of air
through openings in the building envelope driven by pressure differences across
the building shell. The surface pressure driving the air flow include:
- wind
pressure;
- pressures
arising from temperature difference between indoor and outdoor; and
- pressures
resulting from operation of mechanical exhaust.
The infiltration rate of a building depends on weather
conditions, equipment operation and occupant activities. The characteristics of
infiltration air flow may be determined by measuring the air leakage of the
building envelope which describes the relative tightness of a building. Typical
leakage rates are around 6 to 10 air changes per hour at 50 Pa pressure
difference.
Control of infiltration is needed to assure indoor
thermal comfort and to minimise building energy use. Normally, infiltration may
be lessened by reducing the surface pressures driving the air flow, for
instance, through changing the landscaping in the vicinity of the building. A
more common method is to reduce the air leakage of the building shell (for
example, increase air tightness).
Air
leakage area and performance
Air leakage is a measure of the air tightness of
the building envelope. In practical building design, the air tightness of the
whole building or its components is expressed as a leakage rate (in air change
per hour), or an air leakage area.
Building air leakage area is a physical property of
a building determined by its design, construction, seasonal effects, and
deterioration over time. The larger the air leakage, the larger its
infiltration rate. However, no simple relationship exists between a building’s
air tightness and its air exchange rate, although some empirical methods have
been developed to estimate the values.
The air leakage in buildings may be determined by
pressurisation testing or tracer gas measurement. Ratings for air tightness
have been established in some standards based on air flow rates predicted at
particular reference pressures and test conditions. In some cases, the
predicted air flow rate is converted to an equivalent or effective air leakage
area using the following equation (which is derived from the Bernoulli equation
for incompressible fluid flow):
|
|
(8) |
|
where |
|
= effective air leakage area (cm2) |
|
|
|
Qr |
= predicted air flow rate at |
|
|
|
|
= density of air (kg/m3) |
|
|
|
|
= reference pressure difference (Pa) |
|
|
|
CD |
= discharge coefficient |
|
For the whole-building case, all the openings in
the building envelope are combined into an overall opening area and discharge
coefficient for the building when the effective air leakage area is calculated.
Therefore, the air leakage area of a building is the area of an orifice (with
an assumed CD value of 1 or 0.6) that would produce the same amount
of leakage as the building envelope at the reference pressure.
The air leakage performance level for buildings is
sometime presented as leakage classes (such as Class A, B, C and so on) and the
appropriate classes are specified in building regulations based on climate.
Table 3 shows the percentages distribution of air leakage for residential
building components. It can be seen that the walls is the most important
component, followed by ceiling details and heating system.
Table 3 Percentages of air leakage for
residential building components
|
|
Percentage of whole-building air leakage
area |
|
|
Components |
Range |
Mean |
|
Walls |
18 - 50% |
35% |
|
Ceiling details |
3 - 30% |
18% |
|
Heating system (furnace, ducts) |
3 - 28% |
18% |
|
Windows and doors |
6 - 22% |
15% |
|
Fireplaces |
0 - 30% |
12% |
|
Vents in conditioned spaces |
2 - 12% |
5% |
|
Diffusion through walls |
<1% |
|
Estimation
of infiltration rates
In the absence of any detailed information about
the building, a simplified procedure may be used to roughly estimate the
infiltration rates arising from both wind and stack effects. The degree of
shielding and the building height are the factors taken into account in this
method.
|
|
(9) |
|
where |
Ae |
= effective leakage area (cm2) |
|
|
|
Vr |
= volume of the room (m3) |
|
|
|
Q |
= infiltrated air flow rate (m3/h) |
|
|
|
Q/Ae |
= specific infiltration (m3/h.cm2) |
|
In this equation, the specific infiltration may be
calculated by:
|
|
(10) |
|
where |
A |
= stack coefficient (m6/h2/cm4/K) |
|
|
|
B |
= wind coefficient (m6/h2/cm4/(m/s)2) |
|
|
|
VW |
= average wind speed at local weather
station (m/s) |
|
|
|
|
= average indoor-outdoor temperature
difference (oC) |
|
The values of stack coefficient and wind
coefficient with respect to the different shielding levels are given in Table
4.
Table
4 Stack coefficient and wind coefficient
|
|
Number of storeys |
||
|
Description |
One |
Two |
Three |
|
Stack coefficient |
0.00188 |
0.00376 |
0.00564 |
|
Wind coefficient |
|
|
|
|
- no obstruction or local shielding |
0.00413 |
0.00544 |
0.00640 |
|
- light shielding, few obstructions |
0.00319 |
0.00421 |
0.00495 |
|
- moderate local shielding |
0.00226 |
0.00299 |
0.00351 |
|
- heavy shielding |
0.00135 |
0.00178 |
0.00209 |
|
- very heavy shielding |
0.00041 |
0.00054 |
0.00063 |
Air
leakage of building component
Additional test procedures for pressure-testing individual
building components are also available. The component leakage data are useful
to building design since they could be used to determine a more accurate
picture of the likely air leakage performance. Table 5 shows effective air
leakage areas for some building components. The values in the table give
results in terms of air leakage area per unit component. Per unit component
means per component, per unit surface area, or per unit length of crack or
sash, whichever is appropriate. The air leakage areas may be converted to the
results at other reference pressures, air flow rates, or flow coefficients
using some empirical equations.
Table
5 Effective air leakage areas of building components
|
Building components |
Unit |
Best estimate |
Range |
|
Ceiling |
|
|
|
|
-
general |
cm2/m2 |
1.8 |
0.79
- 2.8 |
|
-
drop |
cm2/m2 |
0.19 |
0.046
- 0.19 |
|
-
recessed lights |
cm2/each |
10 |
1.5
- 21 |
|
-
surface-mounted lights |
cm2/each |
0.82 |
|
|
Doors |
|
|
|
|
-
single, not weatherstripped |
cm2/each |
21 |
12
- 53 |
|
-
single, weatherstripped |
cm2/each |
12 |
4
- 27 |
|
-
double, not weatherstripped |
cm2/m2 |
11 |
7
- 22 |
|
-
double, weatherstripped |
cm2/m2 |
8 |
3
- 23 |
|
-
interior (stairs) |
cm2/lmc |
0.9 |
0.25
- 1.5 |
|
-
mail slot |
cm2/lmc |
4 |
|
|
Walls
(exterior) |
|
|
|
|
-
cast-in place concrete |
cm2/m2 |
0.5 |
0.048
- 1.8 |
|
-
clay brick cavity wall (finished) |
cm2/m2 |
0.68 |
0.05
- 2.3 |
|
-
precast concrete panel |
cm2/m2 |
1.2 |
0.28
- 1.65 |
|
-
low-density concrete block (unfinished) |
cm2/m2 |
3.5 |
1.3
- 4 |
|
-
low-density concrete block (painted) |
cm2/m2 |
1.1 |
0.52
- 1.1 |
|
-
high-density concrete blk. (unfinished) |
cm2/m2 |
0.25 |
|
|
Windows |
|
|
|
|
-
awning, not weatherstripped |
cm2/m2 |
1.6 |
0.8
- 2.4 |
|
-
awning, weatherstripped |
cm2/m2 |
0.8 |
0.4
- 1.2 |
|
-
casement, not weatherstripped |
cm2/lmc |
0.28 |
|
|
-
casement, weatherstripped |
cm2/lmc |
0.24 |
0.1
- 3 |
|
-
double-hung, not weatherstripped |
cm2/lmc |
2.5 |
0.86
- 6.1 |
|
-
double-hung, weatherstripped |
cm2/lmc |
0.65 |
0.2
- 1.9 |
|
-
single-hung, weatherstripped |
cm2/lms |
0.87 |
0.62
- 1.24 |
|
-
single horizontal slider, weatherstripped |
cm2/lms |
0.67 |
0.2
- 2.06 |
|
-
single horizontal slider, wood |
cm2/lms |
0.44 |
0.27
- 0.99 |
|
-
single horizontal slider, aluminium |
cm2/lms |
0.8 |
0.27
- 2.06 |
|
-
storm inside, heat shrink |
cm2/lms |
0.018 |
0.009
- 0.018 |
|
-
window sill |
cm2/lmc |
0.21 |
0.139
- 0.212 |
|
Electrical
outlets/switches |
|
|
|
|
-
no gaskets |
cm2/each |
2.5 |
0.5
- 6.2 |
|
-
with gaskets |
cm2/each |
0.15 |
0.08
- 3.5 |
|
Piping/plumbing/wiring
penetrations |
|
|
|
|
-
uncaulked |
cm2/each |
6 |
2
- 24 |
|
-
caulked |
cm2/each |
2 |
1
- 2 |
|
Vents |
|
|
|
|
-
bathroom with damper closed |
cm2/each |
10 |
2.5
- 20 |
|
-
bathroom with damper open |
cm2/each |
20 |
6.1
- 22 |
|
Notes: |
1. lmc = linear metre of crack; lms
= linear metre of sash. |
|
|
2. Data based on a pressure
difference of 4 Pa and CD = 1. |
|
|
3. Data source: 1997 ASHRAE
Fundamental Handbook, Chp. 25. |
The building envelope of large commercial buildings
are often thought to be quite air tight, but in fact many cases indicate that
some components and the workmanship of them may affect the performance
significantly. The infiltration calculations usually focus on doors and windows
which are the obvious weak points. Lift, stair, service shaft walls; floors;
and other internal partitions are also the major separating elements of concern
in these buildings.
In large buildings, the air leakage associated with
internal partitions is very important for evaluating internal air flow. Their
leakage characteristics are needed to determine infiltration through exterior
walls and air flow patterns within the building. These internal resistances are
very essential for two aspects:
- in
the event of a fire, to predict smoke movement patterns and determine smoke management
strategies; and
- to
support air movement calculations when designing air distribution systems.
NATURAL
VENTILATION CALCULATION – FITNESS SUITE NO. 1
Q = Cd
. A [ ( 2 / rins) rins . g . (hnpl – h )
(Tins - Tout / Tins ) ]
where;
Q = Air flow rate
through a large opening (m3/s)
Cd = Discharge
coefficient (0.61 for large openings)
A = Opening area
(m2)
rins = Air
density inside stack (kg/m3)
g = Acceleration
due to gravity (9.81 m/s2)
hnpl = Height
of neutral pressure level above datum (m)
h = Height
of opening above datum (m)
Tout = Temperature of air outside stack (oK)
Tins = Temperature of air inside stack (oK)
DATA
Assuming initial height of stack at 15 metres.
20 ACH/Hr for natural ventilation
Temperature inside stack 24 Deg.C, eins = 1.17 Kg/m3
Formula A = Area ( free Area ) required opening m2
DATA:
The flow rate required for the Fitness Suite is 20
air changes per hour.
The room measures internally 38 m x 17 m x 4m high.
The Fresh air louvre has a 50% free area.
Air flow rate for room Q = Room volume x Air change rate / 3600
Q = 39.4
x 21 x 4.5 x 20
/ 3600
Q = 74,520 /
3600 = 20.7 m3/s
A = Q / cd ( ( 2 / eins ) eins x
g x ( h npl –h ) x Tins – Tout / Tins )
A = 20.7 / 0.61 ( 1.17 x 1.17 x 9.81 x 9 x 0.167
A = 20.7 / 0.61 ( 29.5 )
A = 20.7 = 20.7
0.61 x 29.5 17.995
A = 1.15m2
Area at low level required = 1.15m2 free area.
To fit a louvre @ 50% free Area
opening size = 1.15 x 2 = 2.3m2
Louvre size = 1.52m x 1.52m. at base of stack.
Comment
To provide a stack or chimney to provide this type of ventilation is of
course very energy efficient
However restrictions on the build ( Architectural and other ) need to be
discussed at a very early stage.
Effectiveness
The
effectiveness of natural ventilation for commercial buildings depends on
several criteria. These are wind strength and direction, size of openings, air
temperatures and height of building. For effective controlled ventilation the
designer should not rely solely on the wind but more on the stack effect and
air controls.
Dampers
can be used to control air entering and/or exiting a natural ventilation
system. These dampers could be linked to occupancy sensors, temperature
sensors, time switches and other weather sensors to give automatic control of
ventilation which is the key to a useful system.
Cooling loads, energy requirements and peak
summertime temperatures
QUESTION NO. 5
5.
Use
the CIBSE guide to calculate solar irradiance on a vertical, horizontal and
pitched surface of the Leisure building.
INTRODUCTION
Energy from the Sun reaching the Earth drives almost
every known physical and biological cycle in the Earth system. By making solar
radiation calculations and examining radiation measurements, students can gain
a better understanding of many physical cycles and concepts associated with the
Earth system.
A detailed study of solar irradiance will give Earth & Space Science and
Physics students a better understanding of:
Solar radiation
Electromagnetic spectrum
Mathematical concepts that apply to solar radiation
Climate variation due to latitude
Seasonal weather changes
Global energy balance
Daily changes in solar radiation
Changes in solar irradiance due to solar cycles
Effects of solar irradiance variations on the earth
system
This educational brief is designed to serve as a source
of background information on solar radiation studies and as a reference for
student investigations on this subject. Links to student investigations can be
found at the end of this brief. Before beginning a detailed investigation of
solar radiation, there are three terms that must be understood.
Irradiance - The amount of electromagnetic energy
incident on a surface per unit time per unit area. In the past this quantity
has often been referred to as "flux".
* When measuring solar irradiance (via satellite), scientists are measuring the
amount of electromagnetic energy incident on a surface perpendicular to the
incoming radiation at the top of the Earth's atmosphere, not the output at the
solar surface.
Solar Constant - The solar constant is the amount of
energy received at the top of the Earth's atmosphere on a surface oriented
perpendicular to the Sun’s rays (at the mean distance of the Earth from the
Sun). The generally accepted solar constant of 1368 W/m2 is a
satellite measured yearly average.
Insolation - In general, solar radiation is
received at the Earth's surface. The rate at which direct solar radiation is
incident upon a unit horizontal surface at any point on or above the surface of
Earth. *I will refer to insolation as direct solar radiation at the Earth's
surface.
The solar constant is an important value for
current studies of global radiation balance & climate models. The problem
that faces scientists studying Earth’s radiation budget and climate is that
while satellites can “accurately” measure solar irradiance and calculate a
solar constant, the surface insolation is much more difficult to assess. When
the solar constant is calculated there are four major problems in trying to
relate this radiation intensity to its effect on the Earth's surface or surface
insolation.
First, the calculation is made for the top of the
atmosphere and not for the surface of the Earth.
Second, the calculation assumes that the surface
receiving the radiation is perpendicular to the radiation.
Third, the calculation assumes that the surface
receiving the radiation is at a mean Sun-Earth distance.
Fourth, the calculation assumes that radiation
emission from the Sun remains constant.
Trying to relate calculations made for the top of
the atmosphere to the surface is a problem because up to 70% of incoming
radiation can be blocked by the atmosphere and cloud cover. In attempts to
create global energy budget models, scientists must insert estimations for the
amount of energy actually reaching the surface.
Assuming that the surface receiving the radiation is perpendicular to the
incoming radiation is a problem because this is a rare occasion even at
tropical latitudes due to the rotation of the Earth (time of day), tilt of the
Earth's axis in relation to the incoming solar radiation (season), and the
latitude and orientation of the surface. All of these factors change the angle
of the surface receiving the radiation, which changes the intensity of the
energy received.
Assuming that the radiation emission of the Sun is constant is a problem
because this value fluctuates with cycles in solar activity. NASA satellites
have measured incoming radiation since 1978 and have recorded changes in solar
irradiance. This data can be accessed on the internet from Goddard Space Flight
Center.
SOLAR
RADIATION AND THE ELECTROMAGNETIC SPECTRUM
The electromagnetic spectrum consists of the entire
range of frequencies and wavelengths at which electromagnetic waves can travel.
The electromagnetic spectrum organizes energy types by wavelength and
frequency. The peak wavelength of radiation emitted from an object is dependent
upon the temperature of the object and can be calculated using the Wien
Displacement Law when the temperature of the object is known. (In astronomy
these are solid objects such as stars and planets.)
Wien Displacement Law:
maximum =
2897 / T
maximum =
The peak wavelength of energy in
micrometers
T = The temperature of the object radiating energy
Using this law, the peak wavelength of radiation
emitted from an object is inversely proportional to the temperature of the
object. The irradiance or radiation output of an object can be calculated using
the Stefan-Boltzman Law when the temperature is known.
Stefan-Boltzman Law: E = ![]()
T4
E = Surface Irradiance of the object
*
=
Emissivity of the object
=
Stefan-Boltzman Constant (5.67x10-8 W/m2K4 )
T = Temperature of the object
*Emissivity is the factor of how well a surface can
absorb and emit energy. Emissivity numbers range from 0 to 1. Very black
objects such as charcoal have an emissivity near 1 while shiny objects have an
emissivity near 0.
The Wien Displacement
& Stefan-Boltzman laws strictly apply only to black bodies. Black bodies are
capable of absorbing and emitting radiation at all wavelengths. Because the Sun
& Earth are not perfect black bodies, applying these laws to them only
allows approximate values to be obtained. The fact that the Sun is not a
perfect black body is especially important when studying solar cycles. The most
significant variations in solar radiation during these cycles occur in the UV
& X-Ray portions of the solar spectrum. In order to compare solar emissions
to black body emissions at the same temperature go to the Solar
Spectrum/Black Body Graph.
SOLAR
RADIATION ENTERING THE EARTH SYSTEM
In order to study the effects of solar radiation on
the Earth system, it is necessary to determine the amount of energy reaching
the Earth's atmosphere & surface. Once the surface irradiance of the Sun is
determined the amount of energy reaching the top of the Earth's atmosphere can
be calculated using the Inverse Square Law. The average amount of energy
received on a surface perpendicular to incoming radiation at the top of the
atmosphere is the solar constant. (*While this calculation can lead to a better
student understanding of the Inverse Square Law, the accepted value is a yearly
average from NASA satellite measurements.)
Solar Radiation Striking the top of the Earth's
Atmosphere
The Inverse Square Law is used to calculate the
decrease in radiation intensity due to an increase in distance from the
radiation source.
Inverse Square Law: I = E(4
x R2)/(4
x r2)
I = Irradiance at the surface of the outer sphere
E = Irradiance at the surface of the object (Sun)
4
x R2
= surface area of the object
4
x r2
= surface area of the outer sphere
In order to calculate the solar constant the following
equation is used:
So = E(Sun) x (R(Sun) / r)2
So = Solar Constant
E= Surface Irradiance of the Sun
R= 6.96 x 105 km = Radius of the Sun
r = 1.5 x 108 km =Average Sun-Earth Distance
Insolation: Solar Radiation Striking the Surface
I = S cos Z
I= Insolation
S~ 1000 W/m2 (Clear day solar insolation
on a surface perpendicular to incoming solar radiation. This value actually
varies greatly due to atmospheric variables.)
Z = Zenith Angle (Zenith Angle is the angle from
the zenith (point directly overhead) to the Sun's position in the sky. The
zenith angle is dependent upon latitude, solar declination angle, and time of
day.)
Z = cos-1 (sin
sin
+ cos
cos
cos H)
= Latitude
H = = Hour Angle = 15o x (Time - 12) (Angle of radiation due to time
of day. Time is given in solar time as the hour of the day from midnight.)
= Solar
Declination Angle
Solar Declination Angles for the Northern
Hemisphere
Vernal Equinox Mar. 21/22
= 0o
Summer Solstice Jun. 21/22
= +23.5o
Autumnal Equinox Sept. 21/22
= 0o
Winter Solstice Dec. 21/22
= -23.5o
IRRADIANCE
DATA SOURCES
In addition to making calculations for solar
irradiation based upon physics concepts, students can access & analyze solar
irradiance data that is collected by orbiting satellites and ground based
pyranometers. Satellite irradiance data is available from 1978 to the present
on the internet. The irradiance data has been collected by the following NASA
satellites.
Nimbus 7 (Earth Radiation Budget) 1978- 1993
Solar Maximum Mission: Active Cavity Radiometer Irradiance Monitor I (ACRIM I)
1980-1989
Earth Radiation Budget Satellite (ERBS) Solar Monitor Measurements 1984- 1996
Upper Atmosphere Research Satellite (UARS) ACRIM II Measurements 1991-1997
Data and further information related to these
satellites is available through the NASA Goddard Space
Flight Center Data Archive Center.
SOLAR IRRADIANCE CALCULATIONS LEISURE CENTRE
Information
from CIBSE Guide J (2002) Table 5.11 - Monthly Mean Daily Irradiation in
Includes
Beam + Diffuse = Total Irradiation on 30o inclined plane - South
facing
|
Daily Irradiation from CIBSE
guide |
|
||
|
Month |
Daily
Irradiation (Wh/m2) |
Days per
month |
Monthly Irradiation (Wh/m2) |
|
January |
1002 |
31 |
31,062 |
|
February |
1732 |
28 |
48,496 |
|
March |
2582 |
31 |
80,042 |
|
April |
4051 |
30 |
121,530 |
|
May |
5051 |
31 |
156,581 |
|
June |
4868 |
30 |
146,040 |
|
July |
4868 |
31 |
150,908 |
|
August |
4117 |
31 |
127,627 |
|
September |
3292 |
30 |
98,760 |
|
October |
1994 |
31 |
61,814 |
|
November |
1104 |
30 |
33,120 |
|
December |
679 |
31 |
21,049 |
|
Total
per year |
- |
|
1,076,633 |
SOLAR IRRADIANCE
CALCULATION VERTICAL SURFACE
South facing wall Fitness Suite No. 1
25.0 x 9.2 = 230m2 x 2,544 x 365 = 2135,68800
Kilo
watt hours.
SOLAR IRRADIANCE
CALCULATION HORIZONTAL SURFACE
Ridge
line of Fitness Suite No. 1
7.2m2
x 77,130 Wh/m2 = 555,336 Kilo watt hours.
SOLAR IRRADIANCE
CALCULATION PITCHED SURFACE
South facing
roof over Fitness Suite No. 1
Area = 48m2 x
30% = 62.4m2
62.4 m2 x 1,076,633 Wh/m2 = 671,81899.2
Kilo watt hours.
QUESTION NO. 6
6.
Discuss a system of reducing solar cooling loads in the Leisure
Centre building.
External window shading devices such as awnings, roof overhangs, shutters, and solar screens, and internal
shading devices such as curtains and blinds, can control the entry of solar
heat. However, shutters, solar screens, curtains, and blinds make rooms dark.
Curtains and blinds also let in some of the undesirable heat. While exterior
shading devices are about 50% more effective than internal devices at blocking
solar heat, they may create problems with the building's aesthetics
and are sometimes expensive to build. It is also impractical to construct roof
overhangs to effectively shade east and west facing windows.
The following are the percentages of the radiant
energy that different types of internal shading devices transmit, reflect, or
absorb:
Roller Shades: up to 25%, 15-80%, 20-65%
Vertical Blinds: 0%, 23%, 77%
Venetian Blinds: 5%, 40-60%, 35-55%
The weak thermal characteristics of windows became
a prime target for research and development in the attempt to control indoor
temperatures of buildings. This led to the development of low-emissivity or
"low-e," glass and films that control heat gain and loss, reduce
glare, minimize fabric fading, provide privacy, and occasionally provide added
security in wind, seismic, and other high-hazard zones. New construction and window replacement applications commonly use glazing with
these coatings.
Some low-e coatings and solar control films reduce
solar heat gain without impairing visible light transmission excessively. These
include tinted glass and spectrally selective coatings, which transmit visible
light while reflecting the long-wave infrared portion of sunlight. Many
spectrally selective coatings also have some low-e properties as well. Modern
window glazing falls into three categories: chemically or physically altered
glass, coated glass or films, and multiple-layered assemblies with or without
either of the first two items.
Chemically or Physically Altered Glass
Tinting is the oldest of all the modern window
technologies and, under favorable conditions, can reduce solar heat gain during
the cooling season by 25% to 55%. Tinted glass is made by alteration of the
chemical properties of the glass. Both glass and plastic laminate may be
tinted. The tints absorb a portion of the sunlight and solar heat before it can
pass all the way through the window to the room. Tinted glazings reduce the
latter by 25-55%. "Heat absorbing" tinted glass maximizes its absorption across some, or all, of the solar spectrum.
Unfortunately, the absorbed energy often transfers by radiation and convection
to the inside.
Spectrally selective tints reduce infrared light
(heat) transmission while allowing relatively more visible light to pass
through (compared to bronze- or gray-tinted glass). For buildings that use
daylight for lighting, a spectrally selective window is a good choice.
Spectrally selective glass also absorbs much of the ultraviolet (UV) portion of
the solar spectrum. In a multi-paned window, they function best as the
outermost sheet of glazing. Thermal performance is increased when combined with
a low-e coating. Spectrally selective coatings often have a light blue or green
tint.
Coatings and Films
Low-e and reflective coatings usually consist of a
layer of metal a few molecules thick. The thickness and reflectivity of
the metal layer (low-e coating) and the location of the glass it is attached to
directly affects the amount of solar heat gain in the room. Most window
manufacturers now use one or more layers of low-e coatings in their product
lines.
Any low-e coating is roughly equivalent to adding
an additional pane of glass to a window. Low-e coatings reduce long-wave
radiation heat transfer by 5 to 10 times. The lower the emissivity value
(a measure of the amount of heat transmission through the glazing), the better
the material reduces the heat transfer from the inside to the outside. Most
low-e coatings also slightly reduce the amount of visible light transmitted
through the glazing relative to clear glass. Here are representative emissivity
values for different types of glass:
Clear glass, uncoated: 0.84
Glass with single hard coat low-e: 0.15
Glass with single soft coat low-e: 0.10
A pyrolytic coating baked on at a high temperature
constitutes a "hard coat" low-e coating. These are often made of a
metallic oxide. One layer is about 1/10,000 the diameter of a human hair.
"Soft coat" low-e coatings are applied to
the glass at lower temperatures and even thinner thicknesses than hard
coatings. Both types of low-e coatings (within insulated glazing assemblies)
are typically warranted for 10 to 50 years.
The only spectrally selective coatings now
available are modified soft coat low-e coatings. The selective properties of
the coatings are determined by modifying the coating's thickness and number of
layers. A spectrally selective tinted glazing with a pyrolytic hard coat serves
a similar purpose. These spectrally selective hard coats are currently under
development.
"Aftermarket" films are available for
application on existing windows. They are relatively easy to apply on glazing up 36
square inches (91.5 square centimeters). They are often applied to the glass
with a water soluble adhesive. To reduce the possibility of bubbles and
wrinkles on large windows, have the film installed professionally. Most films
should be applied to the inside surface of the glass since they can be damaged
easily by weather. If you plan to install the film yourself, be careful to
select the appropriate film for your needs, and understand all directions
before beginning. Plastic films generally last about 8 to 10 years before they
start looking worn.
Performance Selection
The key measures of window performance are the
U-Factor, Solar Heat Gain Coefficient, and Visible Transmittance. The air
leakage rating (measure of the rate of air loss around a window under a
specific pressure differential) is also important, but not addressed here.
The U-Factor is a measure of how easily heat
travels through a material. The lower the value, the lower the amount of heat transfer through the window (from the interior to the
exterior). Some manufacturers rate thermal performance using R-Factors.
R-Factor is the inverse of the U-Factor, i.e., 1/U = R, 1/R = U. For example: a
U-Factor of 0.25 is the same as an R-Factor of 4.0. The overall or
"total" or "whole window" U-Factor of any window depends on
the type of glazing, frame materials and size, glazing coatings, and type of
gas (air, or inert argon or krypton) between the panes. Some typical U-Factor
ranges for different window assemblies are:
Single glazed: 0.91 - 1.11
Double glazed: 0.43 - 0.57
Triple glazed: 0.15 - 0.33
The Solar Heat Gain Coefficient (SHGC) is
the fraction of solar heat that enters the window and becomes heat. This
includes both directly transmitted and absorbed solar radiation. The lower the SHGC, the less solar heat that
the window transmits through the glazing from the exterior to the interior, and
the greater its shading ability. In general, South facing windows in houses
designed for passive solar heating (with a roof overhang to shade them in the
summer) should have windows with high a SHGC to allow in beneficial solar heat
gain in the winter. East or West facing windows that get a lot of undesirable
sun in mornings and afternoons, and windows in houses in hot climates, should have
lower SHGC assemblies.
The visible transmittance (VT) refers to the
percentage of the visible spectrum (380-720 nanometers) that is transmitted
through the glazing. When daylight in a space is desirable, as in showrooms and
studios, high VT glazing is a logical choice. However, low VT glazing such as
bronze, gray, or reflective-film windows are more logical for office buildings
or where reducing interior glare is desirable. A typical clear, single-pane
window has a VT of 0.90, meaning it admits 90% of the visible light.
The ratio between SHGC and VT is called the
light-to-solar gain ratio (LSG.) This provides a gauge of the relative
efficiency of different glass types in transmitting daylight while blocking
heat gains. The higher the ratio number the brighter the room is without adding
excessive amounts of heat.
Here are typical values for the Total Window and
|
Window and Glazing Types |
SHG |
VT |
LSG |
|
Single-glazed, clear |
0.79 (0.86) |
0.69 (0.90) |
0.87 (1.04) |
|
Double-glazed, clear |
0.58 (0.76) |
0.57 (0.81) |
0.98 (1.07) |
|
Double-glazed, bronze |
0.48 (0.62) |
0.43 (0.61) |
0.89 (0.98) |
|
Double-glazed, spectrally selective |
0.31 (0.41) |
0.51 (0.72) |
1.65 (1.75) |
|
ouble-glazed, spectrally selective |
0.26 (0.32) |
0.31 (0.44) |
1.19 (1.38) |
|
Triple-glazed, new low-e |
0.37 (0.49) |
0.48 (0.68) |
1.29 (1.39) |
Factors to consider when choosing windows are:
climate, building design, building orientation, and external shading.
Check with manufacturers for product specifications.
Calculating Energy Savings
Energy savings from solar control glazing are
difficult to accurately predict. Predictions of savings are based on many
variables such as: size and orientation of the windows, solar heat gain
coefficient (SHGC), and the cooling load factor (CLF; the ratio of actual total
cooling compared with total steady-state cooling during the same period at
constant ambient conditions.) To make this somewhat simpler, some references
combine these variables into one figure: the Heat Transfer
Multiplier (HTM). The HTM will vary with
location, seasonal changes, time of day, shading, orientation, temperature, and
building color.
There are also computer programs for sizing of
heating/cooling systems. These can also be used to estimate solar heat gain
from different types of windows (given the SHGC and climate). Typically, you
run the same program for each choice in window type and find the dollar value
of the difference in energy saved between the choices. You can then divide the
purchase price by the estimated savings to determine simple payback.
Some solar control films are very costly and may have
very long payback periods. In such cases it may make better sense to consider
other shading devices such as awnings, overhangs, solar screens, shutters,
roller shades, blinds, and draperies.
QUESTION NO. 7
7.
Determine the total heat gain for the Activity Area in the
Leisure Centre building.
Tabulate the data and draw
conclusions from the data.
Compare the total heat gain using
manual calculations with using Hevacomp software.
Heat Gain Calculations
HEAT GAIN
CALCULATION FOR ACTIVITY ROOM
Section 1- Window Sensible Heat Gain
Qg = Ag Ug ( to – tr )
Qg = 219 x 2.0 x ( 27 – 21 )
Qg = 219 x 2.0 x 6
Qg = 2628 watts = 2.628 kW
Where;
Qg = Sensible heat
gain through glass (W)
Ag = Surface area
of glass (m2)
Ug = 'U' value for
glass (W/m2 oC) (see CIBSE guide A (2006) Table 3.23 to 3.32).
to = outside air
temperature (oC). Can be obtained from CIBSE Guide J (2002) - Tables
5.36
to 5.38 for various months and times in the day.
tr = room air
temperature (oC)
Section 2- Solar Glass Gain
Qsg = Fc Fs qsg Ag
= 0.91 x 0.54 x 314 x 219
= 33,791 watts = 33.8 kW
where Qsg = Actual cooling load (W)
qsg = Tabulated
cooling load from CIBSE Guide A (2006) Table 5.19 to 5.24 (W/m2)
Fc = Air
node correction factor from CIBSE Guide A (2006) Table 5.19 to 5.24 or see Table below.
Fs = Shading
factor from CIBSE Guide A (2006) Table 5.19 to 5.24 or see Table below.
Ag = Area
of glass (m2)
The Air point
control factors (Fc) and Shading factors (Fs) are given
in the Table below for various types of glass, building weights and for open
and closed blinds.
|
Air node correction factors (Fc) |
|||||
|
|
Building Weight |
Single Glazing |
Double glazing |
||
|
Horizontal blind |
Horizontal blind |
||||
|
Light |
0.91 |
0.91 |
|||
|
Heavy |
0.83 |
0.90 |
|||
|
Shading factors (Fs) |
|||||
|
Type of glass |
Building Weight |
Single Glazing |
Double glazing |
||
|
|
Open horizontal blind |
Closed horizontal blind |
Open horizontal blind |
Closed horizontal blind |
|
|
Clear 6mm |
Light |
1.00 |
0.77 |
0.95 |
0.74 |
|
Heavy |
0.97 |
0.77 |
0.94 |
0.76 |
|
|
Bronze tinted 6mm |
Light |
0.86 |
0.77 |
0.66 |
0.55 |
|
Heavy |
0.85 |
0.77 |
0.66 |
0.57 |
|
|
Bronze tinted 10mm |
Light |
0.78 |
0.73 |
0.54 |
0.47 |
|
Heavy |
0.77 |
0.73 |
0.53 |
0.48 |
|
|
Reflecting |
Light |
0.64 |
0.57 |
0.48 |
0.41 |
|
Heavy |
0.62 |
0.57 |
0.47 |
0.41 |
|
Section 3- Infiltration Gain
Qsi = N
V ( to – tr ) / 3
Qsi = 0.75
x 21 x 18 x 4.5 ( 27 – 21 ) / 3
Qsi = 2551.5
watts = 2.55kW
where Qsi = Sensible heat gain (W)
n = number of air changes per hour (h-1)
(see note below)
V = volume of room (m3)
to = outside air
temperature (oC) Can be obtained from CIBSE Guide J (2002) - Tables 5.36 to
5.38 for various months and times in the day.
tr = room air temperature (oC)
Infiltration gains
should be added to the room heat gains.
Recommended
infiltration rates are 1/2 air change per hour for most air-conditioning cases
or 1/4 air change per hour for double glazing or if special measures have been
taken to prevent infiltration.
We have used ¾ air
change for this case.
Ventilation or fresh
air supply loads can be added to either the room or central plant loads but
should only be accounted for once.
Section 4- Internal Gains
Occupants = 30
people x 210 watts / persons = 6300 watts
Lighting = Compact
florescent
= 500 Lux = 14 w/m2 x 21 x 18
= 5292 watts = 5.292 Kw
Machinery = 30
No. rowing machines @ 100 watts each
= 3000 watts = 3.0Kw
Sub Total = 14.592
Heat Gain from
internal walls for the Activity Room only The South, east and West walls will
Have any significant
heat gain.
The heat flow
through a wall is complicated by the presence of thermal capacity, so that some
of the heat passing through it is stored, being released at a later time
similar to the use of storage heaters storing heat via economy seven tariff at
night into concrete pattern blocks for releasing heat during the day.
Thick heavy walls
with a high thermal capacity will damp temperature swings considerably, whereas
thin light walls with a small thermal capacity will have little damping effect,
and fluctuations in outside surface temperature will be apparent almost
immediately.
The thermal capacity
will not affect the daily mean solar gain but will affect the solar gain at a
particular time.
The particular time
q of a solar gain is normally the time of the maximum gain.
The heat gain
arrives at the inside of a thick wall some time after the sun hits the outside
surface of the wall.
This time lag is f.
The calculation is,
therefore, again split into two components.
1. Mean gain through
wall,
Qq = A
. U ( tem - tr)
where, Qq = heat gain through wall at time q
A = area
of wall (m2)
U = overall thermal transmittance (W/m2 oC) (see CIBSE guide A
(2006) Table 3.49 to 3.55) for typical
wall constructions.
tem = 24
hour mean sol-air temperature (oC) CIBSE Guide J (2002) - Table 5.36 to 5.38.
tr = constant
dry resultant temperature (oC). In practice room dry bulb is used.
2. The variation
from the mean solar gain is subject to both a decrement factor and time lag.
Qf = f ( teo - tem)
where Qf = Heat
gain through wall at time (q - f)
f = time lag in hours (see CIBSE guide
A (2006) Table 3.49 to 3.55) for typical
wall constructions.
teo = sol-air
temperature at time (q - f) (oC) CIBSE Guide J (2002) - Table 5.36 to 5.38.
tem = 24
hour mean sol-air temperature (oC) CIBSE Guide J (2002) - Table 5.36 t 5.38.
f = decrement factor (see CIBSE guide
A (2006) Table 3.49 to 3.55) for typical
wall constructions.
Therefore the Solar
Gain through a wall at time ( q - f) is;
Qq+f = A . U ( tem - tr) + f ( teo -